CSIR UGC NET Question Papers for Chemical Science will be made available here. The language of the question paper will be Bilingual (Hindi, English). The exam duration will be of 03 hours. Candidates can check the CSIR UGC NET Dec 2018 Question Paper for Chemical Sciences from this page when the question paper will be available it will be updated on this page.
Exam: CSIR UGC NET
Subject: Chemical Science
Session: Dec 2018
CSIR UGC NET Chemical Science Question Paper Dec 2018
In the paper, Multiple Choice Questions (MCQ) will be asked. In the examination question will be asked from Chemical Sciences, Earth, Atmospheric, Ocean and Planetary Sciences, Life sciences, Mathematical Sciences, Physical sciences subjects. CSIR NET Question Paper will be divided into three parts namely Part A, Part B, Part C.
About CSIR NET 2018
CSIR NET examination is conducted twice in a year. In the month of June and December, CSIR NET exam is conducted. CSIR awards Junior Research Fellowship (JRF) to a large number of candidates each year. Educational background of candidates includes BS-4 years program, BE, B.Tech, B.Pharma, MBBS, Integrated BS-MS, MSc or equivalent, B.Sc Hons.
About UGC CSIR NET June 2018
Total 7247 candidates are selected for the JRF and SRF lectureship. Total 1991 and 1500 number of candidates have qualified the JRF (NET) CSIR and JRF (NET) UGC respectively. Total 3756 number of candidates are qualified for Lectureship (NET).
CSIR UGC NET Chemical Science Question Paper Dec 2017
CSIR UGC NET Chemical Science Question Paper for December 2017 is given below.
More CSIR UGC NET Chemical Science Question Paper
Candidates who are looking for CSIR UGC NET Chemical Science Question paper and Answer key for previous years can get them from the table below.
|Year||Question Paper||Answer Key|
|Dec 2017||Click Here||Click Here|
|Jun 2017||Click Here||Click Here|
|Dec 2016||Click Here||Click Here|
|Jun 2016||Click Here||Click Here|
|Dec 2015||Click Here||Click Here|
|Jun 2015||Click Here||Click Here|
|Dec 2014||Click Here||Click Here|